document.write( "Question 710756: Need help please
\n" ); document.write( "Find the slope-intercept form of the line satisfying the given conditions
\n" ); document.write( "parallel to y = 3x + 1, passing through (0,0)
\n" ); document.write( "Have to show work
\n" ); document.write( "Thank you \n" ); document.write( "

Algebra.Com's Answer #437293 by KMST(5328) $\"\"$ $\"About$

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The slope-intercept form of the equation of a line is
\n" ); document.write( " $\"y=mx%2Bb\"$ where the constant $\"m\"$ is the slope,
\n" ); document.write( "and $\"b\"$ is the intercept, the y-coordinate of the point where the line crosses the y-axis.
\n" ); document.write( " $\"y+=+3x+%2B+1\"$ is a line with slope $\"highlight%28m=3%29\"$ that crosses the y-axis at (0,1).
\n" ); document.write( "The slope is the \"steepness\" of the line, the increase in y as x increases by 1.
\n" ); document.write( "With a slope of 3, and starting from point (0,1) with x=0, and y=1,
\n" ); document.write( "increasing x to x=1, we get to the point with y=1+3=4, point (1,4).
\n" ); document.write( "From there, increasing x by 1 to x=2, we get to the point with y=4+3=7, point (2,7).
\n" ); document.write( "Parallel lines have the same slope, and (0,0) would be the point where the new line crosses the y-axis,
\n" ); document.write( "with y-coordinate=0, so $\"highlight%28b=0%29\"$ and
\n" ); document.write( " $\"highlight%28y=3x%2B0%29\"$ or $\"highlight%28y=3x%29\"$ is your answer. \n" ); document.write( "

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