document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=711080>Question 711080</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A man investes R90000 at 16% compound annually.calculate the amount of money he receives if he invests it for seven years </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #437292 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=437292\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A man investes R90000 at 16% compound annually.calculate the amount of money he receives if he invests it for seven years<BR>\n" );
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document.write( "A = P(1+r)^t<BR>\n" );
document.write( "where<BR>\n" );
document.write( "A is amount after time t (what we're looking for)<BR>\n" );
document.write( "P is principal (9000)<BR>\n" );
document.write( "r is rate (.16)<BR>\n" );
document.write( "t is time (7)<BR>\n" );
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document.write( "A = 9000(1+.16)^7<BR>\n" );
document.write( "A = 9000(1.16)^7<BR>\n" );
document.write( "A = 9000(2.82621973446656)<BR>\n" );
document.write( "A = RS25435.98\r<BR>\n" );
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