document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=711049>Question 711049</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The area of the sector of a circle,whose radius is 6 metre when the angle at the centre is 42 degrees,is? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #437274 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=437274\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The area of the sector of a circle,whose radius is 6 metre when the angle at the centre is 42 degrees,is?<BR>\n" );
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document.write( "Area of a sector: (1/2) r^2 x, r=radius, x=central angle in radians<BR>\n" );
document.write( "42º=(42/180)&#960; radians<BR>\n" );
document.write( "Area of sector of given circle=(1/2)(6^2)((42/180)&#960;&#8776;13.19 m^2 </SPAN>\n" );
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