document.write( "Question 711055: Please help me solve the following: a 12 liter antifreeze solution is made up of water and alcohol. How much pure alcohol must be added to raise the concentration from 20% to 50%? \n" ); document.write( "
Algebra.Com's Answer #437270 by lwsshak3(11628)\"\" \"About 
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Please help me solve the following: a 12 liter antifreeze solution is made up of water and alcohol. How much pure alcohol must be added to raise the concentration from 20% to 50%?
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\n" ); document.write( "let x=amt of pure alcohol to add
\n" ); document.write( "20%*12=2.4 liters (amt of pure alcohol in original solution)
\n" ); document.write( "2.4/12=20%
\n" ); document.write( "(2.4+x)/(12+x)=50%
\n" ); document.write( "2.4+x=6+.5x
\n" ); document.write( ".5x=3.6
\n" ); document.write( "x=7.2
\n" ); document.write( "amt of pure alcohol to add=7.2 liters
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