document.write( "Question 710892: Anne is twice the age of Jim. In six years, their ages will total 60. How old is each now? I tried doing it but this came out:
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document.write( "A+J+6+6=60
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document.write( "A+J+12=60
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document.write( "A+J=48
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document.write( "2J+J=48 (because A=2J)
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document.write( "3J=48
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document.write( "J=12, A=24, but it's wrong! \n" );
document.write( "
Algebra.Com's Answer #437233 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Anne is twice the age of Jim. In six years, their ages will total 60. How old is each now? \n" ); document.write( "** \n" ); document.write( "let x=Jim's age \n" ); document.write( "2x=Anne's age \n" ); document.write( "In 6 years: \n" ); document.write( "x+6=Jim's age \n" ); document.write( "2x+6=Anne's age \n" ); document.write( "x+6+2x+6=60 \n" ); document.write( "3x=60-12 \n" ); document.write( "3x=48 \n" ); document.write( "x=16 \n" ); document.write( "2x=32 \n" ); document.write( "Jim's age=16 \n" ); document.write( "Anne's age=32 \n" ); document.write( "You just missed the last step! \n" ); document.write( " |