document.write( "Question 710892: Anne is twice the age of Jim. In six years, their ages will total 60. How old is each now? I tried doing it but this came out:
\n" ); document.write( "A+J+6+6=60
\n" ); document.write( "A+J+12=60
\n" ); document.write( "A+J=48
\n" ); document.write( "2J+J=48 (because A=2J)
\n" ); document.write( "3J=48
\n" ); document.write( "J=12, A=24, but it's wrong!
\n" ); document.write( "

Algebra.Com's Answer #437233 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
Anne is twice the age of Jim. In six years, their ages will total 60. How old is each now?
\n" ); document.write( "**
\n" ); document.write( "let x=Jim's age
\n" ); document.write( "2x=Anne's age
\n" ); document.write( "In 6 years:
\n" ); document.write( "x+6=Jim's age
\n" ); document.write( "2x+6=Anne's age
\n" ); document.write( "x+6+2x+6=60
\n" ); document.write( "3x=60-12
\n" ); document.write( "3x=48
\n" ); document.write( "x=16
\n" ); document.write( "2x=32
\n" ); document.write( "Jim's age=16
\n" ); document.write( "Anne's age=32
\n" ); document.write( "You just missed the last step!
\n" ); document.write( "
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