document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=7183>Question 7183</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is 52 inches. If the length of the rectangle is 2 inches more than twice its width, what are the demensions of the rectangle. Can you show me the operation to solve?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #4372 by </B><A HREF=/tutors/aboutme.mpl?userid=CharStar><B>CharStar(110)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CharStar><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=4372\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The formula for a rectangle is P=2(length+width)<BR>\n" );
document.write( "W=x<BR>\n" );
document.write( "L=2+w\r<BR>\n" );
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document.write( "52=2(w+w+2)\r<BR>\n" );
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document.write( "52=2w+2w+4 Subtract 4 from both sides and add the 2w + 2w<BR>\n" );
document.write( "48=4W<BR>\n" );
document.write( "12=W<BR>\n" );
document.write( "Width = 12<BR>\n" );
document.write( "Length = 14<BR>\n" );
document.write( "Check you answer \r<BR>\n" );
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document.write( "p=2(12+14)<BR>\n" );
document.write( "P=24+28<BR>\n" );
document.write( "Perimeter is 52\r<BR>\n" );
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document.write( "I hope that helps you. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );