document.write( "Question 710803: How to find integers when one third of the sum of three consecutive odd integers is 91? \n" ); document.write( "

Algebra.Com's Answer #437196 by josgarithmetic(39618) $\"\"$ $\"About$

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(2n+1+2n+3+2n+5)/3=91
\n" ); document.write( "(6n+9)/3=91
\n" ); document.write( "2n+3=91
\n" ); document.write( "2n=88
\n" ); document.write( "n=44\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The numbers are 89, 91, 93 \n" ); document.write( "

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