document.write( "Question 710759: a square has an area of 225 the length gets increased but the width stay the same to make a rectangle. the rectangle's perimeter is 5 times the perimeter of the square how many square cm did the rectangle area increase? \n" ); document.write( "
Algebra.Com's Answer #437190 by ankor@dixie-net.com(22740)\"\" \"About 
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a square has an area of 225
\n" ); document.write( "x^2 = 225
\n" ); document.write( "x = \"sqrt%28225%29\"
\n" ); document.write( "x = 15 cm is one side of the original square
\n" ); document.write( "then
\n" ); document.write( "4(15) = 60 cm is the perimeter of the square
\n" ); document.write( ":
\n" ); document.write( " the length gets increased but the width stays the same to make a rectangle. the rectangle's perimeter is 5 times the perimeter of the square
\n" ); document.write( "let a = amt the length gets increased
\n" ); document.write( "2(a+15) + 2(15) = 5(60)
\n" ); document.write( "2a + 30 + 30 = 300
\n" ); document.write( "2a = 300 - 60
\n" ); document.write( "2a = 240
\n" ); document.write( "a = 120 cm increase in length
\n" ); document.write( ":
\n" ); document.write( " how many square cm did the rectangle area increase?
\n" ); document.write( "Area increase: (120+15)*15 - 225 = 1800 sq/cm increase
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