document.write( "Question 710637: A company producing steel construction bars uses the function R(x) = -0.06x^2+10.2x -50 to model the unit revenue in dollars for producing x bars. For what number of bars is the revenue at a maximum? What is the unit revenue at that level of production?\r
\n" ); document.write( "\n" ); document.write( "Having a hard time understanding this problem. \n" ); document.write( "
Algebra.Com's Answer #437116 by nerdybill(7384)\"\" \"About 
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A company producing steel construction bars uses the function R(x) = -0.06x^2+10.2x -50 to model the unit revenue in dollars for producing x bars. For what number of bars is the revenue at a maximum?
\n" ); document.write( "Because the leading coefficient is negative, we KNOW the parabola opens downwards. This means the vertex is the MAXIMUM.
\n" ); document.write( "the x-value of the vertex is:
\n" ); document.write( "x = -b/(2a)
\n" ); document.write( "x = -10.2/(2*(-0.06))
\n" ); document.write( "x = -10.2/(-0.12)
\n" ); document.write( "x = 85 bars
\n" ); document.write( ".
\n" ); document.write( "What is the unit revenue at that level of production?
\n" ); document.write( "find the revenue by plugging it back into the original equation:
\n" ); document.write( "R(x) = -0.06x^2+10.2x -50
\n" ); document.write( "R(85) = -0.06(85)^2+10.2(85) -50
\n" ); document.write( "R(85) = -433.5 + 867 - 50
\n" ); document.write( "R(85) = $383.50
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