document.write( "Question 710606: find 3 consecutive even integers such that 4times the first minus twice the third is equal to the second.
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Algebra.Com's Answer #437085 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( " let \"x\" be first even integer\r
\n" ); document.write( "\n" ); document.write( "\"x+%2B+2\" second even integer\r
\n" ); document.write( "\n" ); document.write( "\"x+%2B+4\" third even integer\r
\n" ); document.write( "\n" ); document.write( "if \"4\" times the \"first\" minus \"twice\" the \"third\" is \"equal\" to the \"second\", we have\r
\n" ); document.write( "\n" ); document.write( "\"4x-2%28x+%2B+4%29=x+%2B+2\"..........solve for \"x\"\r
\n" ); document.write( "\n" ); document.write( "\"4x-2x-8=x+%2B+2\"\r
\n" ); document.write( "\n" ); document.write( "\"2x-8=x+%2B+2\"\r
\n" ); document.write( "\n" ); document.write( "\"2x-x=8+%2B+2\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28x=10%29\"........first even integer\r
\n" ); document.write( "\n" ); document.write( "\"x+%2B+2\" \r
\n" ); document.write( "\n" ); document.write( "\"10+%2B+2\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%2812%29\"..........second even integer\r
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\n" ); document.write( "\n" ); document.write( "\"x+%2B+4\" \r
\n" ); document.write( "\n" ); document.write( "\"10+%2B+4\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%2814%29\"..........third even integer\r
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