document.write( "Question 62671: Please help me to sketch the following line by method of Linear Function or straight lines.
\n" ); document.write( "7. y = (2/3)x-4
\n" ); document.write( "8. 8x-3y=24
\n" ); document.write( "9. slope=-3/4\r
\n" ); document.write( "\n" ); document.write( "Thanks, I am grateful for your help. \n" ); document.write( "
Algebra.Com's Answer #43706 by checkley71(8403)\"\" \"About 
You can put this solution on YOUR website!
Y=(2/3)X-4 THIS REPRESENTS A LINE WITH A SLOPE OF 2/3 & A Y INTERCEPT OF (0,-4)
\n" ); document.write( "TO FIND A SECOND POINT ON THIS LINE SET Y=0 & SOLVE FOR X THUS
\n" ); document.write( "0=(2/3)X-4
\n" ); document.write( "(2/3)X=4
\n" ); document.write( "X=4*3/2
\n" ); document.write( "X=6 OR (6,0) IS A SECOND POINT.
\n" ); document.write( "---------------------------------------------------------------------------
\n" ); document.write( "8X-3Y=24
\n" ); document.write( "-3Y=-8X+24
\n" ); document.write( "Y=(-8/-3)X+24/-3
\n" ); document.write( "Y=(8/3)X-8 THIS IS A LINE WITH A SLOPE OF 8/3 & A Y INTERCEPT OF -8 (0,-8)
\n" ); document.write( "AGAIN TO FIND THE X INTERCEPT SET Y=0
\n" ); document.write( "0=(8/3)X-8
\n" ); document.write( "(8/3)X=8
\n" ); document.write( "X=8*3/8
\n" ); document.write( "X=3
\n" ); document.write( "----------------------------------------------------
\n" ); document.write( "SLOPE=-3/4 IS A LINE THAT GOES FROM A POINT TO THE LEFT (NEGATIVE SLOPE) & UP.
\n" ); document.write( "FOR EVERY 4 UNITS LEFT YOU NEED TO GO 3 UNITS UP. \n" ); document.write( "
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