document.write( "Question 710506: If two people start travel at the same time going in the same direction but at different rates, how do you find the time one catches up to the other?
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Algebra.Com's Answer #437025 by KMST(5347) $\"\"$ $\"About$

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If two people start travel at the same time going in the same direction,
\n" ); document.write( "the faster one will get ahead,
\n" ); document.write( "and the other will never catch up.
\n" ); document.write( "The slower person could catch up if the faster one stops or slows down.
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\n" ); document.write( "The typical catch up problem involves the slower person/vehicle starting earlier, and the faster one starting later and catching up
\n" ); document.write( " $\"f\"$ = speed of the fast one
\n" ); document.write( " $\"s\"$ = speed of the slow one
\n" ); document.write( " $\"t\"$ = time since the slow one started
\n" ); document.write( " $\"d\"$ = delayed start time of the fast one
\n" ); document.write( "At any time after the fast one starts,
\n" ); document.write( "the slow one has covered a distance of $\"s%2At\"$ ,
\n" ); document.write( "while the fast one has been traveling for $\"t-d\"$ ,
\n" ); document.write( "covering a distance of $\"%28t-d%29f\"$
\n" ); document.write( "When the fast one catches up, both have covered the same distance and
\n" ); document.write( " $\"%28t-d%29f=st\"$ \n" ); document.write( "

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