document.write( "Question 710520: I have a gallon of lemonade that is 20% lemon juice. I like it better when it is 25% juice. How much juice should I add?\r
\n" ); document.write( "\n" ); document.write( "I know that I need to add 5% more lemon juice, so do I need to just figure out how to say 5/100 gallons? ... Like in quarts or something?
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Algebra.Com's Answer #437023 by KMST(5328)\"\" \"About 
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A lemonade that is 25% lemon juice would have
\n" ); document.write( "\"25%2F100=0.25\" gallons of lemon juice in
\n" ); document.write( "exactly \"1\" gallon of lemonade.
\n" ); document.write( "A lemonade that is 20% lemon juice has
\n" ); document.write( "\"20%2F100=0.20\" gallons of lemon juice in
\n" ); document.write( "exactly \"1\" gallon of lemonade.
\n" ); document.write( "If you add \"5%2F100\" gallon lemon juice, you will have a total of
\n" ); document.write( "\"1%265%2F100\" gallons = \"1.05\" gallons of lemonade containing \"20%2F100%2B5%2F100=25%2F100\" or \"0.20%2B0.05=0.25\" gallons of lemon juice.
\n" ); document.write( "That will not be exactly 25% lemon juice.
\n" ); document.write( "In fact, the percentage is \"%280.25%2F1.05%29%2A100\"% = about \"23.8\"%\r
\n" ); document.write( "\n" ); document.write( "\"x\" = gallons of lemon juice to add
\n" ); document.write( "\"1%2Bx\" = final volume of lemonade (in gallons)
\n" ); document.write( "\"1%2A0.20\" = gallons of lemon juice in original \"1\" gallon of lemonade
\n" ); document.write( "\"%281%2Bx%29%2A0.25\" = gallons of lemon juice in final mixture
\n" ); document.write( "\"1%2A0.20%2Bx=%281%2Bx%29%2A0.25\"
\n" ); document.write( "\"0.20%2Bx=0.25%2B0.25x\"
\n" ); document.write( "\"0.20%2Bx-0.25x=0.25\"
\n" ); document.write( "\"x-0.25x=0.25-0.20\"
\n" ); document.write( "\"0.75x=0.05\" --> \"0.75x%2F0.75=0.05%2F0.75\" --> \"highlight%28x=1%2F15%29\" = approx. \"0.0633\" gallons.
\n" ); document.write( "The number does not get prettier in quarts:
\n" ); document.write( "\"1%2F15\"gallon = \"4%2F15\"quarts
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