document.write( "Question 710263: what are the vertex, focus and directrix of parabola 12y=x^2-6x+45? have so far: (x-3)^2=12(y-3). vertex is (3,3) or (-3,-3)???? how do I do focus and directrix? \n" ); document.write( "
Algebra.Com's Answer #436991 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! what are the vertex, focus and directrix of parabola \n" ); document.write( "12y=x^2-6x+45? \n" ); document.write( "x^2-6x=12y-45 \n" ); document.write( "complete the square: \n" ); document.write( "(x^2-6x+9)=12y-45+9 \n" ); document.write( "(x-3)^2=12y-36 \n" ); document.write( "(x-3)^2=12(y-3) \n" ); document.write( "This is an equation of a parabola that opens upwards. \n" ); document.write( "Its standard form: (x-h)^2=4p(y-k), (h,k)=(x,y) coordinates of the vertex \n" ); document.write( "For given equation:(x-3)^2=12(y-3) \n" ); document.write( "vertex: (3,3) \n" ); document.write( "axis of symmetry: x=3 \n" ); document.write( "4p=12 \n" ); document.write( "p=3 \n" ); document.write( "focus: (3,6) (p-units above vertex on the axis of symmetry) \n" ); document.write( "directrix: y=0 (p-units below vertex on the axis of symmetry) \n" ); document.write( " |