document.write( "Question 710351: A solution if 52% fertilizer is to be mixed with a solution of 22% fertilizer to form 90 liters of a 42% solution. How many of the 52% solution must be used? \n" ); document.write( "
Algebra.Com's Answer #436973 by josgarithmetic(39617)![]() ![]() ![]() You can put this solution on YOUR website! This one is the same general problem as question #710342. Different materails, different mixture unit, different values; but the same problem.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "VARIABLES \n" ); document.write( "High concentration fertilizer percent, H =52% \n" ); document.write( "Low concentration fertilizer percent, L =22% \n" ); document.write( "Target percent wanted, T = 42% \n" ); document.write( "Amount of High conce. to use, v \n" ); document.write( "Amount of Low conce. to use, u \n" ); document.write( "Amount of target mixture produced, M = 90 Liters\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This system can be formed from the description and question \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If we use the second equation as \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now, just substitute the values and compute u. \n" ); document.write( "We can then go to our simpler-looking expression for v and find (compute) it, too. |