document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=62882>Question 62882</A>: <I><SPAN STYLE=\"word-break: break-all;\"> -3x+2y=2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #43697 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=43697\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I'LL ASSUME THIS IS A LINE EQUATION SEEING AS IT IS UNDER THE GRAPH CATEGORY.<BR>\n" );
document.write( "-3X+2Y=2<BR>\n" );
document.write( "2Y=3X+2<BR>\n" );
document.write( "Y=3/2X+1<BR>\n" );
document.write( "THIS IS A LINE WITH A SLOPE OF 3/2 OR 1.5 & A Y INTERCEPT OF (0,1)<BR>\n" );
document.write( "TO FIND ANOTHER INTERCEPT SET Y=0 AND SOLVE FOR X<BR>\n" );
document.write( "0=3/2X+1<BR>\n" );
document.write( "3/2X=-1<BR>\n" );
document.write( "3X=-2<BR>\n" );
document.write( "X=-2/3 THUS A SECOND POINT IS (-2/3,0)  </SPAN>\n" );
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