document.write( "Question 710342: If a 7% saline solution and a 4% saline solution are mixed to make 500 milliliters of a 5% saline solution, how much of each solution, to the nearest milliliter, is needed? \n" ); document.write( "
Algebra.Com's Answer #436969 by josgarithmetic(39617)![]() ![]() ![]() You can put this solution on YOUR website! CHOOSING VARIABLES FOR ALL NUMBERS \n" ); document.write( "Concentration of Low percent saline, L \n" ); document.write( "Concentration of High percent saline, H \n" ); document.write( "Target concentration of saline wanted, T \n" ); document.write( "Amount of Low concentration saline to use, u, unknown \n" ); document.write( "Amount of High concentration saline to use, v, unknown \n" ); document.write( "Amount of saline solution made, M, or 500 ml. in the example\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "From problem description: \n" ); document.write( "L=4%, H=7%, T=5%, M=500 ml.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Create Equations to Represent Situation:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Solve that system for u and v. \n" ); document.write( " \n" ); document.write( "Use the volume sum equation for known mixture volume amount to substitute for v. \n" ); document.write( "Using v=M-u, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You could substitute the given values into this formula for u, and then compute u. Then, use the u+v=M relationship to compute v. \n" ); document.write( " |