document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=62864>Question 62864</A>: <I><SPAN STYLE=\"word-break: break-all;\">   jack has a traingular room that needs carpeting . how much carpeting will he need if the hypotenuse and one of the legs measure 24feet and 30feet respectively. show your work.  thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #43694 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=43694\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I'LL ASSUME THE HYPOTENUSE (LONGEST SIDE)IS 30 FEET AND ONE SIDE IS 24.<BR>\n" );
document.write( "A^2+B^2=C^2<BR>\n" );
document.write( "24^2+B^2=30^2<BR>\n" );
document.write( "576+B^2=900<BR>\n" );
document.write( "B^2=900-576<BR>\n" );
document.write( "B^2=324<BR>\n" );
document.write( "B=SQRT324<BR>\n" );
document.write( "B=18 SOLUTION FOR THE SECOND SIDE.<BR>\n" );
document.write( "THEN THE TOTAL AREA IS LENGTH*WIDTH (SIDE1*SIDE2)<BR>\n" );
document.write( "18*24=432 SQUARE FEET<BR>\n" );
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document.write( "I CALCULATE DTHE AREA OF A RECTANGLE (18 BY 24) THE TRIANGLR IS 1/2 OF THIS AREA THUS 432*1/2=216 SQ FOOT.<BR>\n" );
document.write( "AGAIN THIS ASSUMES THE HYPOTENUSE IS THE 30 FOOT MEASUREMENT.   </SPAN>\n" );
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