document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=710252>Question 710252</A>: <I><SPAN STYLE=\"word-break: break-all;\"> \r<BR>\n" );
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document.write( "The second angle of a triangular garden is four times as large as the first. The third angle is 45 degrees less than the sum of the other two angles. Find the measure of each angle.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #436937 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley79><B>checkley79(3341)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley79><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=436937\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> SECOND ANGLE=4 TIMES THE FIRST.<BR>\n" );
document.write( "S=4F<BR>\n" );
document.write( "THE THIRD ANGLE=F+S-45<BR>\n" );
document.write( "F+S+T=180<BR>\n" );
document.write( "F+(4F)+(F+[4F]-45)=180<BR>\n" );
document.write( "10F-45=180<BR>\n" );
document.write( "10F=180+45<BR>\n" );
document.write( "10F=225<BR>\n" );
document.write( "F=225/10<BR>\n" );
document.write( "F=22.5 DEGREES.<BR>\n" );
document.write( "S=4*22.5=90 DEGREES.<BR>\n" );
document.write( "22.5+90+T=180<BR>\n" );
document.write( "T=180-22.5-90<BR>\n" );
document.write( "T=67.5 DEGREES.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "22.5+90+67.5=180<BR>\n" );
document.write( "180=180 </SPAN>\n" );
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