document.write( "Question 710190: Find the standard score (z) such that the area above the mean and below z under the normal curve is 0.4882. \n" ); document.write( "
Algebra.Com's Answer #436927 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Find the standard score (z) such that the area above the mean and below z under the normal curve is 0.4882. \n" ); document.write( "--------------- \n" ); document.write( "Draw the picture. \n" ); document.write( "---- \n" ); document.write( "The right tail must be 0.5000-0.4882 = 0.0118 \n" ); document.write( "---- \n" ); document.write( "Find the z-value with a left tail of 0.0118 \n" ); document.write( "invNorm(0.0118) = -2.2636 \n" ); document.write( "--- \n" ); document.write( "By symmetry your answer is +2.2636 \n" ); document.write( "===================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |