document.write( "Question 710221: A box contains 21 yellow, 24 green and 27 red jelly beans.
\n" ); document.write( "If 13 jelly beans are selected at random, what is the probability that:
\n" ); document.write( "a) 10 are yellow?
\n" ); document.write( "b) 10 are yellow and 2 are green?
\n" ); document.write( "c) At least one is yellow?\r
\n" ); document.write( "\n" ); document.write( "Sorry but i dont have the slightest clue how to do this.I would aprreciate the help!
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Algebra.Com's Answer #436926 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
A box contains 21 yellow, 24 green and 27 red jelly beans.
\n" ); document.write( "There are 72 jelly beans.
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\n" ); document.write( "If 13 jelly beans are selected at random, what is the probability that:
\n" ); document.write( "a) 10 are yellow?
\n" ); document.write( "# of ways to succeed: 21C10*51C3
\n" ); document.write( "# of possible outcomes: 72C13
\n" ); document.write( "---
\n" ); document.write( "P(10 yellow) = [21C10*51C3]/72C13 = 0.0001036...
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\n" ); document.write( "b) 10 are yellow and 2 are green?
\n" ); document.write( "P(10 yellow and 2 green) = [21C10*24C2*29C1]/72C13 = 0.000039814
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\n" ); document.write( "c) At least one is yellow = 1 - P(none are yellow)
\n" ); document.write( "= 1 - [51C13/72C13]
\n" ); document.write( "---
\n" ); document.write( "= 0.9933
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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