document.write( "Question 710169: Contract the expressions. That is, use the properties of logarithms to write each expression as a single logarithm with a coefficient of 1. \r
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document.write( "ln 3 − 2 ln 7 + ln 14\r
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document.write( "ln 3 − 2 ln(6 + 6)\r
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document.write( "ln 3 − 2(ln 4 + ln 8) \n" );
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Algebra.Com's Answer #436901 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! write each expression as a single logarithm with a coefficient of 1. \r \n" ); document.write( "\n" ); document.write( "ln 3 − 2 ln 7 + ln 14 \n" ); document.write( "--- \n" ); document.write( "= ln[3*14/7^2] \n" ); document.write( "--- \n" ); document.write( "= ln[6/7] \n" ); document.write( "=====================\r \n" ); document.write( "\n" ); document.write( "ln 3 − 2 ln(6 + 6) \n" ); document.write( "----- \n" ); document.write( "= ln[3/12^2] \n" ); document.write( "--- \n" ); document.write( "= ln[1/48] \n" ); document.write( "==================== \n" ); document.write( " \n" ); document.write( "ln 3 − 2(ln 4 + ln 8) \n" ); document.write( "--- \n" ); document.write( "ln(3)- 2ln(4)- 2ln(8) \n" ); document.write( "=== \n" ); document.write( "ln(3)-ln*16 - ln(64) \n" ); document.write( "----- \n" ); document.write( "= ln[3/(16*64)] \n" ); document.write( "--- \n" ); document.write( "ln[3/1024] \n" ); document.write( "================ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "================= \n" ); document.write( " \n" ); document.write( " |