document.write( "Question 710187: log(3) (2x - 1) = 3 \n" ); document.write( "
Algebra.Com's Answer #436900 by stanbon(75887)\"\" \"About 
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log(3) (2x - 1) = 3
\n" ); document.write( "---
\n" ); document.write( "base = 3
\n" ); document.write( "log = expoent = 3
\n" ); document.write( "result = 2x-1
\n" ); document.write( "---------------------
\n" ); document.write( "Equation:
\n" ); document.write( "2x-1 = 3^3
\n" ); document.write( "2x-1 = 27
\n" ); document.write( "2x = 28
\n" ); document.write( "x = 14
\n" ); document.write( "----------------
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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