document.write( "Question 710162: There is 20 gallons of 20% o.j. How many gallons must be mixed with 80% o.j. to make the mixture have 50% o.j. drink? \n" ); document.write( "

Algebra.Com's Answer #436894 by josmiceli(19441) $\"\"$ $\"About$

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Let $\"+x+\"$ = gallons of 80% OJ needed
\n" ); document.write( " $\"+.8x+\"$ = gallons of OJ in 80% OJ
\n" ); document.write( " $\"+.2%2A20+=+4+\"$ gallons of OJ in 20% OJ
\n" ); document.write( "---------------------------------
\n" ); document.write( " $\"+%28+.8x+%2B+4+%29+%2F+%28+x+%2B+20+%29+=+.5+\"$
\n" ); document.write( " $\"+.8x+%2B+4+=+.5%2A%28+x+%2B+20+%29+\"$
\n" ); document.write( " $\"+.8x+%2B+4+=+.5x+%2B+10+\"$
\n" ); document.write( " $\"+.3x+=+6+\"$
\n" ); document.write( " $\"+x+=+20+\"$
\n" ); document.write( "20 gallons of 80% OJ is needed
\n" ); document.write( "check:
\n" ); document.write( " $\"+%28+.8%2A20+%2B+4+%29+%2F+%28+20+%2B+20+%29+=+.5+\"$
\n" ); document.write( " $\"+%28+16+%2B+4+%29+%2F+40+=+.5+\"$
\n" ); document.write( " $\"+20%2F40+=+.5+\"$
\n" ); document.write( " $\"+.5+=+.5+\"$
\n" ); document.write( "OK
\n" ); document.write( " \n" ); document.write( "

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