document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=710109>Question 710109</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of each side of a square is 3in more than the length of each side of a smaller square. The sum of the areas of the squares is 149in^2. find the lengths of the sides of the two squares.. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #436881 by </B><A HREF=/tutors/aboutme.mpl?userid=sachi><B>sachi(548)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sachi><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=sachi><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=436881\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The length of each side of a square is 3in more than the length of each side of a smaller square.<BR>\n" );
document.write( "let the length of smaller square=x<BR>\n" );
document.write( "the length of big square=x+3\r<BR>\n" );
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document.write( "The sum of the areas of the squares is 149in^2. <BR>\n" );
document.write( "so x^2+(x+3)^2=149<BR>\n" );
document.write( "or x^2+x^2+6x+9=149<BR>\n" );
document.write( "or 2x^2+6x=149-9=140<BR>\n" );
document.write( "or x^2+3x-70=0<BR>\n" );
document.write( "or x^2+10x-7x-70=0<BR>\n" );
document.write( "or x(x+10)-7(x+10)=0<BR>\n" );
document.write( "or (x+10)(x-7)=0<BR>\n" );
document.write( "or x=-10 or 7<BR>\n" );
document.write( "taking + ve value<BR>\n" );
document.write( "the sides of the smaller square=7<BR>\n" );
document.write( "then the sides of the big square =7+3=10 </SPAN>\n" );
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