document.write( "Question 62867: 3logx+3=1 \n" ); document.write( "
Algebra.Com's Answer #43688 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
3logx+3=1
\n" ); document.write( "logx=-2/3
\n" ); document.write( "x=10^(-2/3)
\n" ); document.write( "x=1/[(100)^(1/3)]
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "
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