document.write( "Question 709997: two towns are 1300 miles apart. A group of hikers start from each town and walk the trail toawrd each other. They meet after a total hiking time of 200 hours. If one group travels 2 1/2 mile per hour faster than the other group. find the rate of each group. \n" ); document.write( "
Algebra.Com's Answer #436847 by checkley79(3341)![]() ![]() ![]() You can put this solution on YOUR website! D=RT \n" ); document.write( "1300=(X+2.5X)200 \n" ); document.write( "1300=3.5X*200 \n" ); document.write( "1300=700X \n" ); document.write( "X=1300/700 \n" ); document.write( "X=1.857 MPH. FOR THE SLOWER GROUP. \n" ); document.write( "2.5*4.64 MPH. FOR THE FASTER GROUP. \n" ); document.write( "PROOF: \n" ); document.write( "1300=(1.875+4.64)200 \n" ); document.write( "1300=6,515*200 \n" ); document.write( "1300=1300=1300 \n" ); document.write( " |