document.write( "Question 710001: \r
\n" ); document.write( "\n" ); document.write( "A total of $3000 was invested, part of it at 5% interest and the remainder at 7%. If the total yearly interest amount is $195, how much was invested at 5%?
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Algebra.Com's Answer #436844 by checkley79(3341)\"\" \"About 
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.07X+.05(3000-X)=195
\n" ); document.write( ".07X+150-.02X=195
\n" ); document.write( ".02X=195-150
\n" ); document.write( ".02X=45
\n" ); document.write( "X=45/.02
\n" ); document.write( "X=2250 ANS. FOR THE 7% INVESTMENT.
\n" ); document.write( "3000-2250=750 ANS. FOR THE 5% INVESTMENT.
\n" ); document.write( "PROOF:
\n" ); document.write( ".07*2250+.05*750=195
\n" ); document.write( "157.5+37.5=195
\n" ); document.write( "195=195
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