document.write( "Question 709892: please help me with these questions
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document.write( "1. 25^x=0.2\r
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document.write( "2. ln x=0\r
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document.write( "3.logsquareroot7 x= 2logsquareroot7 3\r
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document.write( "4. 3^2x+1 = 4^2x-1\r
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document.write( "thankyou i only had 4 question \n" );
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Algebra.Com's Answer #436809 by lynnlo(4176) ![]() You can put this solution on YOUR website! (1)x=-0.8047/ln(5) \n" ); document.write( "(2)x=1 \n" ); document.write( "(3)need to re-write this problem i keep getting no-solution, \n" ); document.write( "log √7x=2 log√7,3 \n" ); document.write( "(4)x=2/7 \n" ); document.write( " |