document.write( "Question 709881: Can you show me how to solve x^3-6x^2-9x=0? \n" ); document.write( "
Algebra.Com's Answer #436807 by josh_jordan(263)\"\" \"About 
You can put this solution on YOUR website!
To solve for x, first factor out an x from the left side of the equal sign. This gives us\r
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\n" ); document.write( "\n" ); document.write( "\"x%28x%5E2+-+6x+-+9%29+=+0\"\r
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\n" ); document.write( "\n" ); document.write( "We know know that 0 is one of the values of x.\r
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\n" ); document.write( "\n" ); document.write( "To find the other two values, use the quadratic formula on the quadratic equation inside the parentheis: \"x%5E2+-+6x+-+9\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=%28-%28-6%29%2B-sqrt%28-6%5E2-4%2A1%2A%28-9%29%29%29%2F%282%2A1%29\" = \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%286%2B-sqrt%2836%2B36%29%29%2F2\" =\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%286%2B-sqrt%2872%29%29%2F2\" = \r
\n" ); document.write( "\n" ); document.write( "\"x+=+%286%2B-6%2Asqrt%282%29%29%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "We can reduce this to lowest terms, by factoring out a 6 from the numerator:\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%286%281%2B-sqrt%282%29%29%29%2F2\", then dividing the factored 6, by two, giving us\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+3%281%2B-sqrt%282%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "Therefore, x = 0,\"3%2B3%2Asqrt%282%29%29\",\"3-3%2Asqrt%282%29%29\"
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