document.write( "Question 709876: How do you solve x^3+x=0 ? \n" ); document.write( "
Algebra.Com's Answer #436803 by josh_jordan(263)\"\" \"About 
You can put this solution on YOUR website!
To solve for x, first factor an x from the left side of the equal sign, since x is common to both terms. This gives us\r
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\n" ); document.write( "\n" ); document.write( "x(x^2 + 1) = 0\r
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\n" ); document.write( "\n" ); document.write( "We know that x = 0, because if you multiply any number by 0, you get zero, so if you substitute 0 into the factored equation\r
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\n" ); document.write( "\n" ); document.write( "0(0^2 + 1)\r
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\n" ); document.write( "\n" ); document.write( "We get 0.\r
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\n" ); document.write( "\n" ); document.write( "Now, to find the other values of x, set (x^2 + 1) equal to 0: x^2 + 1 = 0\r
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\n" ); document.write( "\n" ); document.write( "To solve for x, subtract 1 from both sides of the equation, which gives us\r
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\n" ); document.write( "\n" ); document.write( "x^2 = -1\r
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\n" ); document.write( "\n" ); document.write( "Since we are squaring the x, we must take the square root of both sides, to remove the exponent of 2. This gives us\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+sqrt%28-1%29\"\r
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\n" ); document.write( "\n" ); document.write( "Our final two answers for x will be imaginary numbers. Since \"i+=+sqrt%28-1%29\", i will be the second value of x. Remember, when you take the square root of a square, your result is both a positive AND negative number. Therefore, your third and final value of x, is -i\r
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\n" ); document.write( "\n" ); document.write( "Answer: x = 0, i, -i
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