document.write( "Question 709832: write a polynomial function with rational coefficients so that it has roots (-2, 1+3i ) \n" ); document.write( "
| Algebra.Com's Answer #436799 by josgarithmetic(39630)      You can put this solution on YOUR website! You seem to be asking for polynomial function with roots: -2,and 1+3i, AND 1-3i. Complex roots come as conjugate pairs.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-2 is a root: \n" ); document.write( "((-2)-(k))=0 \n" ); document.write( "-2-k=0 \n" ); document.write( "-k=2 \n" ); document.write( "k=-2 \n" ); document.write( "The binomial factor is (x-(-2))= \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "1+3i is a root: \n" ); document.write( "(1+3i-k)=0 \n" ); document.write( "1+3i-k=0 \n" ); document.write( "-k=-1-3i \n" ); document.write( "The binomial factor is (x-(-1-3i)) \n" ); document.write( "or equal to \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "1-3i is a root: \n" ); document.write( "(1-3i-k)=0 \n" ); document.write( "-k=-1+3i \n" ); document.write( "k=1-3i \n" ); document.write( "The binomial factor is \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "A satisfying function can come from \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Do the multiplications, at least for the factors containing the complex numbers: \n" ); document.write( "... The finished polynomial function may be: \n" ); document.write( " |