document.write( "Question 709784: I did group terms and factor each group, now stuck on Distributive property
\n" ); document.write( "for x^3+4x^2+x+4 \n" ); document.write( "

Algebra.Com's Answer #436794 by jsmallt9(3758) $\"\"$ $\"About$

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$\"x%5E3%2B4x%5E2%2Bx%2B4\"$
\n" ); document.write( "Grouping:
\n" ); document.write( " $\"%28x%5E3%2B4x%5E2%29%2B%28x%2B4%29\"$
\n" ); document.write( "Factoring out the GCF. (Note: This point in factoring by grouping is one of the few times you actually factor out a GCF of 1!)
\n" ); document.write( " $\"x%5E2%28x%2B4%29%2B1%28x%2B4%29\"$
\n" ); document.write( "Now we look to see if the two groups have a common factor. (If not, then we need to try something else (factoring out the negative of the GCF from each group and/or changing the groups). But we are fortunate. The two groups do have a common factor of (x+4). Factoring out the (x+4) from the two groups:
\n" ); document.write( " $\"%28x%2B4%29%28x%5E2%2B1%29\"$

\n" ); document.write( "Neither factor will factor further so are finished factoring.

\n" ); document.write( "If you want to check, use FOIL to multiply out the answer. You should end up with $\"x%5E3%2B4x%5E2%2Bx%2B4\"$ . \n" ); document.write( "

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