document.write( "Question 709710: In a 60km bicycle race, a rider calculates that if he can increase his speed by 6km/h he will cut his time for the distance by 20minutes. What was his original speed? \n" ); document.write( "
Algebra.Com's Answer #436765 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! In a 60km bicycle race, a rider calculates that if he can increase his speed by 6km/h he will cut his time for the distance by 20minutes. What was his original speed? \n" ); document.write( ": \n" ); document.write( "Change 20 min to 1/3 hr \n" ); document.write( ": \n" ); document.write( "Let s = original speed \n" ); document.write( "then \n" ); document.write( "(s+6) = increased speed \n" ); document.write( ": \n" ); document.write( "Write a time equation time = dist/speed \n" ); document.write( " \n" ); document.write( "multiply by 3s(s+6) to clear the denominators, resulting in: \n" ); document.write( "3(s+6)(60) + 3s(60) = s(s+6) \n" ); document.write( "180s + 1080 + 180s = s^2 + 6s \n" ); document.write( "A quadratic equation from all this \n" ); document.write( "s^2 + 6s - 1080 = 0 \n" ); document.write( "You can solve this using the quadratic formula if you enjoy that sort of thing. But this will factor to: \n" ); document.write( "(s + 36)(s + 30) = 0 \n" ); document.write( "The positive solution is all we want here \n" ); document.write( "s = 30 km/hr is the original speed \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check this by finding the actual times \n" ); document.write( "60/30 = 2 hrs \n" ); document.write( "60/36 = 1.67 \n" ); document.write( "------------- \n" ); document.write( "differ: .33 hrs which is 20 min \n" ); document.write( " |