document.write( "Question 709684: the base and height of a triangle are (x+3)cm and (2x+5)cm respectively if the area of a triangle is 20 cm square , find x \n" ); document.write( "
Algebra.Com's Answer #436739 by nerdybill(7384)\"\" \"About 
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the base and height of a triangle are (x+3)cm and (2x+5)cm respectively if the area of a triangle is 20 cm square , find x
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\n" ); document.write( "Since area of a triangle is:
\n" ); document.write( "(1/2)bh = area
\n" ); document.write( "plugging in the given data:
\n" ); document.write( "(1/2)(x+3)(2x+5) = 20
\n" ); document.write( "multiplying both sides by 2:
\n" ); document.write( "(x+3)(2x+5) = 40
\n" ); document.write( "FOIL the left:
\n" ); document.write( "2x^2+5x+6x+15 = 40
\n" ); document.write( "2x^2+11x+15 = 40
\n" ); document.write( "2x^2+11x-25 = 0
\n" ); document.write( "applying the \"quadratic equation\" we get:
\n" ); document.write( "x = {1.73, -7.23}
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\n" ); document.write( "details of quadratic follows:
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"2x%5E2%2B11x%2B-25+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%2811%29%5E2-4%2A2%2A-25=321\".
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\n" ); document.write( " Discriminant d=321 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-11%2B-sqrt%28+321+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"x%5B1%5D+=+%28-%2811%29%2Bsqrt%28+321+%29%29%2F2%5C2+=+1.72911821679223\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%2811%29-sqrt%28+321+%29%29%2F2%5C2+=+-7.22911821679223\"
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\n" ); document.write( " Quadratic expression \"2x%5E2%2B11x%2B-25\" can be factored:
\n" ); document.write( " \"2x%5E2%2B11x%2B-25+=+2%28x-1.72911821679223%29%2A%28x--7.22911821679223%29\"
\n" ); document.write( " Again, the answer is: 1.72911821679223, -7.22911821679223.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+2%2Ax%5E2%2B11%2Ax%2B-25+%29\"

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