document.write( "Question 709609: How many liters of 20% alcohol and 75% alcohol must be mixed to obtain 32L of 40% alcohol solution? \n" ); document.write( "
Algebra.Com's Answer #436696 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! How many liters of 20% alcohol and 75% alcohol must be mixed to obtain 32L of 40% alcohol solution? \n" ); document.write( "---- \n" ); document.write( "Equation: \n" ); document.write( "alc + alc = alc \n" ); document.write( "0.20x + 0.75(32-x) = 0.40*32 \n" ); document.write( "---- \n" ); document.write( "20x + 75*32 - 75x = 40*32 \n" ); document.write( "---- \n" ); document.write( "-55x = -35*32 \n" ); document.write( "x = (7/11)32 \n" ); document.write( "---- \n" ); document.write( "x = 20.36 liters (amt. of 20% solution needed) \n" ); document.write( "----- \n" ); document.write( "32-x = 32-20.36 = 11.64 liters (amt. of 75% solution needed) \n" ); document.write( "=================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "=================== \n" ); document.write( " |