document.write( "Question 709438: A college student earned $5500 during summer vacation working as a waiter in a popular restaurant. The student invested part of the money at 8% and the rest at 6%. If the student received a total of $384 in interest at the end of the year, how much was invested at 8%? \n" ); document.write( "
Algebra.Com's Answer #436639 by checkley79(3341)\"\" \"About 
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.08X+.06(5,500-X)=384
\n" ); document.write( ".08X+330-.06X=384
\n" ); document.write( ".02X=384-330
\n" ); document.write( ".02X=54
\n" ); document.write( "X=54/.02
\n" ); document.write( "X=2,700 AMOUNT INVESTED @ 8%.
\n" ); document.write( "PROOF:
\n" ); document.write( ".08*2,700+.06(5,500-2,700)=384
\n" ); document.write( "216+.06*2,800=384
\n" ); document.write( "216+168=384
\n" ); document.write( "384=384
\n" ); document.write( "
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