document.write( "Question 709487:
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document.write( "The Great Pyramid of Giza is one of the Seven Wonders of the World and until the 19 century, was the tallest building in the world. The base of the pyramid measures 756ft and the edges measure 612ft. Each face is an isosceles triangle. Find the area of one of the triangular faces of the pyramid \n" );
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Algebra.Com's Answer #436620 by checkley79(3341) ![]() You can put this solution on YOUR website! YOU HAVE 2 RIGHT TRIANGLES. \n" ); document.write( "BASE=756/2=378 FT. \n" ); document.write( "SIDE=612 FT. \n" ); document.write( "A^2+B^2=C^2 \n" ); document.write( "378^2+B^2=61262 \n" ); document.write( "142884+B^2=374544 \n" ); document.write( "B^2=374544-142884 \n" ); document.write( "B^2=231660 \n" ); document.write( "B=SQRT231660 \n" ); document.write( "B=481.31 FT. THIS IS THE HEIGHT OF THE TRIANGLE. \n" ); document.write( "AREA=BH/2 \n" ); document.write( "AREA=(756*481.31)/2 \n" ); document.write( "AREA=363,870.36/2 \n" ); document.write( "B=181,935.18 FT^2 ANS. \n" ); document.write( " |