document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=709509>Question 709509</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A chainsaw runs on fuel that is 10% oil and 90% gas. How much oil will have to be added to 3 gallons of fuel that is 5% oil and 95% gas in order to use it in the chainsaw? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #436609 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=436609\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A chainsaw runs on fuel that is 10% oil and 90% gas. How much oil will have to be added to 3 gallons of fuel that is 5% oil and 95% gas in order to use it in the chainsaw?<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "oil + oil = oil<BR>\n" );
document.write( "0.05*3 + 1*x = 0.10(3+x)<BR>\n" );
document.write( "----<BR>\n" );
document.write( "5*3 + 100x = 10*3 + 10x<BR>\n" );
document.write( "90x = 5*3<BR>\n" );
document.write( "x = 1/6 gallon (amt. of pure oil needed for the mixture)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );