document.write( "Question 62850: the problem is:\r
\n" ); document.write( "\n" ); document.write( "\"+c%2F2-80b=120+\" and \"+a%2F5%2B2b%2F7=1\"
\n" ); document.write( "(find c in terms of a)\r
\n" ); document.write( "\n" ); document.write( "when i did the second expression, i got 80b=280-56a
\n" ); document.write( "then i substituted this into the first and got
\n" ); document.write( "c=800-112a as my final answer
\n" ); document.write( "is this right??
\n" ); document.write( "thanks
\n" ); document.write( "

Algebra.Com's Answer #43660 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Well, it looks like you got it all right!..
\n" ); document.write( "\"a%2F5+%2B+2b%2F7+=+1\"
\n" ); document.write( "\"%287a+%2B+10b%29%2F35+=+1\"
\n" ); document.write( "\"7a+%2B+10b+=+35\"
\n" ); document.write( "\"10b+=+35+-+7a\"
\n" ); document.write( "\"80b+=+280+-+56a\" Substituting this into the first \"equation\".
\n" ); document.write( "\"c%2F2+-+80b+=+120\"
\n" ); document.write( "\"c%2F2+-+%28280+-+56a%29+=+120\" Simplifying, you get:
\n" ); document.write( "\"c%2F2+%2B+56a+=+400\"
\n" ); document.write( "\"c%2F2+=+400+-+56a\" Multiplying by 2:
\n" ); document.write( "\"c+=+800+-+112a\"
\n" ); document.write( "
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