document.write( "Question 709407: Find the value of p for which the following system of eq has exactly 1 solution 7x-5y-4=0 and 14x+py+4=0 \n" ); document.write( "
Algebra.Com's Answer #436555 by josgarithmetic(39620)\"\" \"About 
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p must be chosen just so that the slopes of the two lines are different. That condition is p<-10 and p>-10. p can be any real number, just not -10.\r
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\n" ); document.write( "\n" ); document.write( "Your equations:
\n" ); document.write( "7x-5y-4=0 and 14x+py+4=0\r
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\n" ); document.write( "\n" ); document.write( "The first one, -5y=-7x+4, y=(7/5)x+4, the slope is (7/5).\r
\n" ); document.write( "\n" ); document.write( "The second equation, py=-14x-4, y=(-14/p)x-4, the slope is variably (-14/p).\r
\n" ); document.write( "\n" ); document.write( "If the slopes of the two lines are DIFFERNT, then the system will have ONE solution. If p=-10, then the second line has slope (-14/-10)=7/5, and is parallel to the first line and then the system has no solution. \r
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\n" ); document.write( "\n" ); document.write( "The only requirement for the two lines meeting in one point is that p NOT equal -10.
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