document.write( "Question 709377: suppose that the function g is defined, for all real numbers, as follows.
\n" ); document.write( "g(x)= -x if x does not equal 3
\n" ); document.write( "g(x)=2 if x equals 3\r
\n" ); document.write( "\n" ); document.write( "graph the function g. \n" ); document.write( "

Algebra.Com's Answer #436548 by jsmallt9(3758) $\"\"$ $\"About$

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Pretend for a moment that the function was simply g(x) = -x then I hope you would recognize this as the equation for a line. A line in slope-intercept form. A line with a slope of -1 and a y-intercept of 0. One of the points on this pretend line is (3, -3)

\n" ); document.write( "Since the real g(x) is -x for all x's except 3, graph the line described above except for the point (3, -3)!. In other words. draw an small open circle (a small ring) at the point (3, -3). (This open circle indicates that this point is not included.) Then draw the rest of the line as normal. When you are finished it should look like the the line y = -x except that it has a \"hole\" in it at (3, -3).

\n" ); document.write( "To finish the graph just plot the point (3, 2). (This is a regular point, a dot, not the open circle we used at (3, -3).)

\n" ); document.write( "Your final graph should be a line with a hole in it at (3, -3) plus the extra point (3, 2) (which is nowhere near the line). \n" ); document.write( "

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