document.write( "Question 709355: Solve the inequality, and express the solutions in terms of intervals whenever possible. (Enter your answer using interval notation. If there is no solution, enter NO SOLUTION.) \r
\n" ); document.write( "\n" ); document.write( "4 < |3x − 3| < 5
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Algebra.Com's Answer #436547 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
Two possiblilities to check. One is if 3x-3>=0 and the other is for 3x-3<0. Before going into more, factor the expression..\r
\n" ); document.write( "\n" ); document.write( "\"3x-3=3%28x-1%29\". Take care of that in the inequality statement.\r
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\n" ); document.write( "\n" ); document.write( "4 < |3x − 3| < 5
\n" ); document.write( "\"4%3C3abs%28x-1%29%3C5\"
\n" ); document.write( "\"4%2F3+%3C+abs%28x-1%29+%3C+5%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "If \"x-1%3E=0\" then:
\n" ); document.write( "\"4%2F3+%3C+x-1+%3C+5%2F3\"
\n" ); document.write( "\"4%2F3%2B1+%3C+x+%3C+5%2F3%2B1\"
\n" ); document.write( "\"7%2F3+%3C+x+%3C+8%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "If x-1<0 then :
\n" ); document.write( "\"4%2F3+%3C+1-x+%3C+5%2F3\"
\n" ); document.write( "\"4%2F3-1+%3C+-x+%3C+5%2F3-1\"
\n" ); document.write( "\"1%2F3+%3C+-x+%3C+2%2F3\"
\n" ); document.write( "Now multiply all members by NEGATIVE 1 and reverse the direction of the order symbols.
\n" ); document.write( "\"-1%2F3+%3E+x+%3E+-2%2F3\"
\n" ); document.write( "And to keep lesser to the left and greater to the right,
\n" ); document.write( "\"-2%2F3+%3C+x+%3C+-1%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "FINAL RESULT STATEMENT: \"-2%2F3+%3C+x+%3C+-1%2F3\" OR \"7%2F3+%3C+x+%3C+8%2F3\"
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