document.write( "Question 709392: Two joggers, one averaging 7mph and one averaging 4mph, start from a disgnated initial point. The slower jogger arrives at the end of the run 40 minutes after the other jogger. Find the distance of the run. \n" ); document.write( "
Algebra.Com's Answer #436545 by josgarithmetic(39628) ![]() You can put this solution on YOUR website! pp \n" ); document.write( "The Joggers__________rate__________time hrs.___________distance \n" ); document.write( "fast_________________7_____________t___________________d \n" ); document.write( "slower_______________4_____________t+2/3_______________d\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The (2/3) of the hour is the same as 40 minutes.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The distance that each jogged is the same, so equate the expressions for their distance, rate in miles per hour multiplied by the hours.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(This result appeared to be about a 10 kilometer event.) \n" ); document.write( " |