document.write( "Question 709392: Two joggers, one averaging 7mph and one averaging 4mph, start from a disgnated initial point. The slower jogger arrives at the end of the run 40 minutes after the other jogger. Find the distance of the run. \n" ); document.write( "
Algebra.Com's Answer #436545 by josgarithmetic(39628)\"\" \"About 
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\n" ); document.write( "The Joggers__________rate__________time hrs.___________distance
\n" ); document.write( "fast_________________7_____________t___________________d
\n" ); document.write( "slower_______________4_____________t+2/3_______________d\r
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\n" ); document.write( "\n" ); document.write( "The (2/3) of the hour is the same as 40 minutes.\r
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\n" ); document.write( "\n" ); document.write( "The distance that each jogged is the same, so equate the expressions for their distance, rate in miles per hour multiplied by the hours.\r
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\n" ); document.write( "\n" ); document.write( "\"7t=4%28t%2B2%2F3%29\", and solve for t in hours. Once t is known, use either joggers data to compute d.\r
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\n" ); document.write( "\n" ); document.write( "\"7t=4t%2B8%2F3\"
\n" ); document.write( "\"3t=8%2F3\"
\n" ); document.write( "\"highlight%28t=8%2F9%29\", hours\r
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\n" ); document.write( "\n" ); document.write( "\"highlight%28d=7%2A%288%2F9%29%29\", miles\r
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\n" ); document.write( "\n" ); document.write( "(This result appeared to be about a 10 kilometer event.)
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