document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=709332>Question 709332</A>: <I><SPAN STYLE=\"word-break: break-all;\"> log base 5 * square root of 125 - log base 2 * square root of 2 = ?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #436542 by </B><A HREF=/tutors/aboutme.mpl?userid=hheuler><B>hheuler(6)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=hheuler><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=hheuler><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=436542\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> log base 5 * square root of 125 - log base 2 * square root of 2\r<BR>\n" );
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document.write( "= log_5 [sqrt(125)] - log_2[sqrt(2)]\r<BR>\n" );
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document.write( "= log_5[5^3]^(1/2) - log_2 [2]^(1/2)\r<BR>\n" );
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document.write( "= log_5 [5]^3/2 - log_2[2]^(1/2)\r<BR>\n" );
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document.write( "= 3/2 - 1/2\r<BR>\n" );
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document.write( "= 1\r<BR>\n" );
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document.write( "We are using the log property that log_a a^b = b.  </SPAN>\n" );
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