document.write( "Question 709251: PLEASE HELP!!!!!!!!!!!!!!!!!!! \r
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document.write( "SOLVE FOR X
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document.write( "2x + y + z = 0
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document.write( "3x - y + z = 3
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document.write( "7x - 5y - 3z = 15\r
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document.write( "thanks. \n" );
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Algebra.Com's Answer #436536 by hheuler(6)![]() ![]() You can put this solution on YOUR website! eq 1 2x + y + z = 0 \n" ); document.write( "eq 2 3x - y + z = 3 \n" ); document.write( "Eq 3 7x - 5y - 3z = 15\r \n" ); document.write( "\n" ); document.write( "Add eq 1 and eq 2: 5x + 2z = 3 and z = 1/2[3 - 5x] eq 4\r \n" ); document.write( "\n" ); document.write( "Subtract eq 1 from eq 2; x - 2y = 3 and y = 1/2[x - 3] eq 5\r \n" ); document.write( "\n" ); document.write( "Substitute eq 4 and eq 5 into eq 3 giving:\r \n" ); document.write( "\n" ); document.write( "7x - 5[1/2(x - 3)] - 3[1/2(3 - 5x)] = 15\r \n" ); document.write( "\n" ); document.write( "Multiply both sides of this equation by 2 to eliminate the fractions and simplify the resulting equation by adding like terms. Isolate the variable x to the left side of the equation. \r \n" ); document.write( "\n" ); document.write( "14x - 5x + 15 - 9 + 15x = 30\r \n" ); document.write( "\n" ); document.write( "24x = 24\r \n" ); document.write( "\n" ); document.write( "x = 1\r \n" ); document.write( "\n" ); document.write( "From eq 4 we have z = 1/2(3 - 5(1)] = -1 \n" ); document.write( "From eq 5, we have y = 1/2[1 - 3] = -1\r \n" ); document.write( "\n" ); document.write( "The solution is (x, y, z) = (1, -1, -1). \n" ); document.write( " \n" ); document.write( " |