document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=709348>Question 709348</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Maria is now four times as old as Kate. Four years ago, Maria was six times as old as Kate. Find each of their actual ages now.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #436531 by </B><A HREF=/tutors/aboutme.mpl?userid=hheuler><B>hheuler(6)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=hheuler><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=hheuler><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=436531\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x represent the age of Kate four years ago. At the same time, Maria was 6x years old.\r<BR>\n" );
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document.write( "At the present time, Kate will be x + 4 years old and Maria will be 6x + 4 years old. We are told that Maria is now four times as old as Kate. So we have the following equation to solve.\r<BR>\n" );
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document.write( "    6x + 4 = 4(x + 4) <BR>\n" );
document.write( "     6x - 2x = 16 - 4<BR>\n" );
document.write( "        2x = 12<BR>\n" );
document.write( "         x = 6\r<BR>\n" );
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document.write( "So Kate is now 6 + 4 = 10 years old and Maria is now 6(6) + 4 = 40 years old.        <BR>\n" );
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