document.write( "Question 709251: PLEASE HELP!!!!!!!!!!!!!!!!!!! \r
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document.write( "SOLVE FOR X
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document.write( "2x + y + z = 0
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document.write( "3x - y + z = 3
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document.write( "7x - 5y - 3z = 15\r
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document.write( "thanks. \n" );
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Algebra.Com's Answer #436528 by KMST(5328)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "I do not like the problem either, but no one answered yesterday, so I'll try today. (Warning: I make stupid mistakes in easy calculations, so watch for my mistakes) \n" ); document.write( "Probably you want to use the elimination method, and not matrices. \n" ); document.write( "You want to combine equations to get 2 combination equations with 2 variables. \n" ); document.write( "(We still have a 3-variable-3-equation system, but we can set aside one of the original equations, with all 3 variables, as our third equation, and not worry about it for now). \n" ); document.write( "Then, we would be able to solve the set of combination equations as a two-variable-two-equation system. \n" ); document.write( " \n" ); document.write( "It looks like the easiest way would be to use the simpler first equation, \n" ); document.write( "combining it with each of the other equations, to eliminate \n" ); document.write( "Subtracting the first equation from the second one you get \n" ); document.write( " \n" ); document.write( "Adding \n" ); document.write( " \n" ); document.write( "Now we solve \n" ); document.write( " \n" ); document.write( "I would subtract the new system's first equation from the other equation to get \n" ); document.write( " \n" ); document.write( "Substituting into \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Then, I would go back to one of the original equations and substitute \n" ); document.write( "I chose \n" ); document.write( " \n" ); document.write( "I verified on my own on scrap paper and it seems to work, \n" ); document.write( "but remember, I warned you that I'm error prone. \n" ); document.write( " |