document.write( "Question 709245: Suppose that the length of a rectangle is 3 in longer than the width and the perimeter ofathe rectangle is 78.\r
\n" ); document.write( "\n" ); document.write( "a. Set up an equatio involving only w, the width of the rectangle
\n" ); document.write( "b. Solve linear equation algebraically to find the width of the rectangle. Find the length as well.
\n" ); document.write( "c. Using the the same length you have as you answer and part b find a new perimeter if the new width is 4 more than one third of the length.
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Algebra.Com's Answer #436505 by josgarithmetic(39618)\"\" \"About 
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x is length. w is width.\r
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\n" ); document.write( "\n" ); document.write( "\"x=w%2B3\"
\n" ); document.write( "AND
\n" ); document.write( "\"2%28x%2Bw%29=78\"\r
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\n" ); document.write( "\n" ); document.write( "FINDING w, WIDTH
\n" ); document.write( "\"highlight%282%28%28w%2B3%29%2Bw%29=78%29\"
\n" ); document.write( "4w+6=78
\n" ); document.write( "w=72/4
\n" ); document.write( "w=18\r
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\n" ); document.write( "\n" ); document.write( "FINDING x, LENGTH
\n" ); document.write( "x=w+3
\n" ); document.write( "x=18+3
\n" ); document.write( "x=21\r
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\n" ); document.write( "\n" ); document.write( "Summary of dimensions
\n" ); document.write( "\"highlight%28x=21%29\", \"highlight%28w=18%29\"
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