document.write( "Question 709245: Suppose that the length of a rectangle is 3 in longer than the width and the perimeter ofathe rectangle is 78.\r
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document.write( "a. Set up an equatio involving only w, the width of the rectangle
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document.write( "b. Solve linear equation algebraically to find the width of the rectangle. Find the length as well.
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document.write( "c. Using the the same length you have as you answer and part b find a new perimeter if the new width is 4 more than one third of the length. \n" );
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Algebra.Com's Answer #436505 by josgarithmetic(39618)![]() ![]() ![]() You can put this solution on YOUR website! x is length. w is width.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "AND \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "FINDING w, WIDTH \n" ); document.write( " \n" ); document.write( "4w+6=78 \n" ); document.write( "w=72/4 \n" ); document.write( "w=18\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "FINDING x, LENGTH \n" ); document.write( "x=w+3 \n" ); document.write( "x=18+3 \n" ); document.write( "x=21\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Summary of dimensions \n" ); document.write( " |