document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=709295>Question 709295</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two sides of a rectangle are parallel to each other and are doneted as y. The other two sides of the rectangle are also parallel to each other and are denoted as x. If the sides x of the rectangle are increased by 3 units, the resulting figure is a square with area 20. What was the original area?\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "My attempt: y(x+3)=20<BR>\n" );
document.write( "             y=x+3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #436499 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39630)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=436499\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You seem about half way there.\r<BR>\n" );
document.write( "\n" );
document.write( "y(x+3)=20.  Substitute!...<BR>\n" );
document.write( "(x+3)(x+3)=20.  Both sides became the same size when the x was lengthened, which is why you equated y and x+3.  The y was not changed but now matches the length of the other direction.\r<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2%2B6x%2B9-20=0 ALIGN=MIDDLE  ALT=\"x%5E2%2B6x%2B9-20=0\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2%2B6x-11=0 ALIGN=MIDDLE  ALT=\"x%5E2%2B6x-11=0\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "x=(-6+- sqrt(36-4*(-11)))/2<BR>\n" );
document.write( "(-6+- sqrt(80))/2<BR>\n" );
document.write( "(-6+-4sqrt(5))/2<BR>\n" );
document.write( "-3+-2sqrt(5)<BR>\n" );
document.write( "The negative not reasonable, so <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=-3%2B2sqrt%285%29 ALIGN=MIDDLE  ALT=\"x=-3%2B2sqrt%285%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "y=x+3<BR>\n" );
document.write( "y=-3+2sqrt(5)+3<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=2sqrt%285%29 ALIGN=MIDDLE  ALT=\"y=2sqrt%285%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Original Area, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28xy=%28-3%2B2sqrt%285%29%29%282sqrt%285%29%29%29 ALIGN=MIDDLE  ALT=\"highlight%28xy=%28-3%2B2sqrt%285%29%29%282sqrt%285%29%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );